Structural & Mechanics

Mohr's Circle Calculator

Enter a plane stress state to get the principal stresses, the maximum shear stress and their orientations, the stresses on any rotated plane and the von Mises stress, with Mohr's circle drawn to scale.

Tool no.
ECT-S06
Rev
1.0
Updated
Oct 2026
Method
Plane stress transformation

How to use this calculator

Enter the two normal stresses and the shear stress acting on an element aligned with x and y. Tension is positive. Shear τxy is positive when it acts in the +y direction on the +x face. Angles are measured counterclockwise from the x-axis. Change θ to read the stresses on any rotated plane; the red dashed line on the circle moves with it.

Formulas

Center and radius of the circleσavg = σx + σy2  R = √((σx − σy)/2)2 + τxy2
Principal stresses and maximum in-plane shearσ1,2 = σavg ± R  τmax = R
Principal angle (to the σ₁ plane)θp = ½ atan2(2τxy, σx − σy)  θs = θp − 45°
Stresses on a plane rotated by θσx′ = σavg + σx − σy2 cos 2θ + τxy sin 2θ  τx′y′ = −σx − σy2 sin 2θ + τxy cos 2θ
von Mises stress for plane stressσvm = √σ12 − σ1σ2 + σ22

On the circle, a rotation of θ on the element is a rotation of 2θ around the circle. The drawing plots point X at (σx, τxy) and Y at (σy, −τxy) with shear positive downward, the convention used in Hibbeler’s Mechanics of Materials, so both rotate in the same direction.

Worked example

σx = 80 MPa, σy = −40 MPa, τxy = 30 MPa (the default)

  1. σavg = (80 − 40)/2 = 20 MPa. R = √(60² + 30²) = 67.08 MPa, which is also τmax.
  2. σ1 = 20 + 67.08 = 87.08 MPa and σ2 = 20 − 67.08 = −47.08 MPa.
  3. θp = ½ atan2(60, 120) = 13.28° counterclockwise from x.
  4. At θ = 30°: σx′ = 20 + 60 cos 60° + 30 sin 60° = 75.98 MPa and τx′y′ = −60 sin 60° + 30 cos 60° = −36.96 MPa.
  5. σvm = √(87.08² + 87.08 × 47.08 + 47.08²) = 117.9 MPa.

In-plane versus absolute maximum shear

For plane stress the third principal stress is σ3 = 0. When σ1 and σ2 have opposite signs, the in-plane maximum shear R is also the absolute maximum. When they have the same sign, the largest shear acts on a plane tilted out of the x–y plane and equals half the larger principal stress. The Tresca yield criterion uses this absolute value.

Assumptions and limits

  • Plane stress: σz, τxz and τyz are zero, as on a free surface or in a thin plate.
  • Stresses are at a single point; they come from your own analysis, such as σ = Mc/I and τ = Tc/J.
  • Linear elastic behavior is assumed when the von Mises stress is compared with yield.

Frequently asked questions

Why does my textbook draw the circle upside down?

Some books plot shear positive upward and place Y at (σy, τxy), which makes the circle rotate opposite to the element. Both conventions give the same principal stresses and angles when used consistently.

How do I use the von Mises stress?

Compare it with the yield strength. For ductile metals, yielding is predicted when σvm reaches σy, so the factor of safety is σy/σvm.

Where do combined stresses come from in practice?

A shaft carrying bending and torque at the same time has σx from bending and τxy from torsion. Get them from the bending stress and shaft torsion calculators, then combine them here.

For education and preliminary checks only. Have a qualified engineer verify any design before it is built.